Biquadratic Equation Solver

    Solve biquadratic equations with the x-squared substitution method, intermediate values, real or complex roots, and a graph of the even polynomial.

    Supports powers 2 and 4, parentheses, decimal coefficients, and a right-hand side. Variable denominators are not supported here.
    Coefficient input
    Quick input
    Equation roots
    Discriminant in t
    9
    positive: two intermediate values
    Intermediate values
    value 1: 1
    value 2: 4
    Symmetry
    The function values mirror across opposite inputs.
    Even function: roots are symmetric around 0.
    Graph of the original polynomial
    What the calculation used
    The equation is reduced to biquadratic form, intermediate values are solved, and real roots are returned.

    A biquadratic equation contains only even powers of the variable. This calculator reduces the input to that form, solves the intermediate equation, and returns real or complex roots.

    How a biquadratic equation is solved

    A biquadratic equation contains only even powers of the variable. It reduces to an ordinary quadratic after substituting an intermediate variable for x squared.

    x is the original unknown; a, b, and c are the biquadratic coefficients.

    t is the intermediate variable used before converting back to x.

    1. Reduce the input to a polynomial with powers 4, 2, and 0
    2. Substitute t for x squared
    3. Solve the intermediate quadratic
    4. Check whether each intermediate value is positive, zero, or negative
    5. Return real roots and show complex pairs separately

    Full equation input

    The tool accepts both coefficients and a full equation string. Parentheses, a right-hand side, implicit multiplication, and decimal coefficients are supported as long as the reduced equation remains biquadratic.

    x is moved to one side before solving the intermediate quadratic.

    x appears only in even powers, so the factored form is valid input.

    How many real roots can appear

    Nonzero real roots appear in opposite-sign pairs because the polynomial is even. A zero root is shown once in the distinct-root list.

    Intermediate valuesReal-root resultMeaning
    Both positiveFour rootstwo opposite-sign pairs
    One positive and one zeroThree distinct rootsone pair plus zero
    One positive and one negativeTwo real rootsnegative t gives complex roots
    Both negativeNo real rootsall x roots are complex
    Intermediate discriminant negativeNo real rootsno real t values

    Input limits

    If an odd power or a degree higher than four appears after expansion, the problem is no longer biquadratic. The calculator reports that instead of switching to a generic quartic solver.

    x appears in a linear term, so the biquadratic structure is broken.

    x has degree five, which is outside this solver.

    Variable denominators
    Numeric fractional coefficients are supported. Rational equations with x in the denominator need a separate domain analysis and are not handled here.

    Even symmetry and graph

    A biquadratic function is symmetric about the y-axis. The graph helps confirm how many times the curve crosses the x-axis.

    f has even symmetry around the y-axis.

    Quick check
    If a nonzero root appears, the opposite value should also be a root.

    Frequently Asked Questions

    Sources and References

    Calculations are based on the listed reference sources. Links open in a new tab.

    Updated:

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